Last updated at Jan. 23, 2020 by Teachoo

Transcript

Example 4 Evaluate ∆ = |■8(0&sin𝛼&−cos𝛼@−sin𝛼&0&sinβ@cos𝛼&−sinβ&0)| ∆ =|■8(0&sin𝛼&−cos𝛼@−sin𝛼&0&sinβ@cos𝛼&−sinβ&0)| = 0(0 + sin2 β) – sin 𝛼 (0 – cos α sin β) – cos 𝛼 (sin 𝛼 sin β – 0) = 0 – sin 𝛼 (–cos 𝛼 sin β ) – cos 𝛼 (sin 𝛼 sin β) = sin 𝛼 cos 𝛼 sin β – cos 𝛼 sin 𝛼 sin β = 0|■8(0&sin𝛽@−sin𝛽&0)| – sin α |■8(−sin𝛼&sin𝛽@cos𝛼&0)| + (–cos 𝛼) |■8(−sin𝛼&0@cos𝛼&−sin𝛽 )| 0 (0(0) – (– sin β) sin β) – sin 𝛼 (– sin 𝛼 (0) – cos 𝛼 sin β) – cos 𝛼 (–sin 𝛼 (–sin β ) – cos 𝛼 (0)) = sin 𝛼 cos 𝛼 sin β – sin 𝛼 cos 𝛼 sin β = 0

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Example 4 You are here

Example 5 Important

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Example 30 Deleted for CBSE Board 2022 Exams

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Example 34 Important Deleted for CBSE Board 2022 Exams

Chapter 4 Class 12 Determinants (Term 1)

Serial order wise

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.